Question

HELP!!!!!!! Dx
If sin theta =2/3 , which of the following are possible?

1. cos theta= -sqrt5/3 and tan theta=2/ sqrt5

2. sec theta= 3/sqrt5 and tan theta= 2/sqrt5

3. sec theta= -3/2 and tan theta= 2/sqrt5

4. cos theta= sqrt5/3 and tan theta= 2/sqrt5

Answer 1

draw a triangle...sin theta = 2/3 = opposite/hypotenuse



that means the third side is \(\sqrt {3^2 - 2^2} = \sqrt{ 9 -4} = \sqrt 5\)

so your adjacent is \(\sqrt 5\)
opposite = 2
hypotenuse = 3

i think from that data you can verify which is correct..

Answer 2

So it's 2 and 4 right?

Answer 3

@JCortez93 --> That is correct.