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OpenStudy (istim):
Determine dy/dx for y=5sqrt(x^3)
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OpenStudy (anonymous):
y=5sqrt(x^3)
= 5(x^(3/2))
dy/dx = 5(3/2)(x^(3/2 -1))
= 15/2 (x^1/2)
OpenStudy (anonymous):
IsTim now you're here for math too? giggle, shiny and math?
OpenStudy (anonymous):
y=x^n
dy/dx = nx^(n-1)
this is the property I use
OpenStudy (istim):
Truly, I don't really understand what derivatives is.
@Ishaan94 Pardon?
OpenStudy (istim):
The Power Rule. Ok.
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OpenStudy (anonymous):
Sorry.
OpenStudy (istim):
It's ok. I don't understand (your speech and derivatives; either/or) though.
OpenStudy (istim):
If you can, please describe each step thoroughly. Thank you.
OpenStudy (istim):
OH well.
OpenStudy (istim):
What's happening at dy/dx = 5(3/2)(x^(3/2 -1)) ?
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OpenStudy (istim):
Or, how did it come to that?
OpenStudy (anonymous):
y=ax^n
dy/dx =a( nx^(n-1))
put a=1 and n=3/2
OpenStudy (istim):
Uhm, sorry to ask, but could you type dy/dx = 5(3/2)(x^(3/2 -1)) in Latex (The Equation Editor)? I don't think I'm understanding it correctly.
OpenStudy (istim):
@CoCoTsoi When you have time, of course.
OpenStudy (anonymous):
|dw:1335423732321:dw|
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