can someone show me how to use partial fractions in integration please? it confuses me...i think i did well in this during the algebra course...i dont know lol maybe i need a refresher :DDD
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OpenStudy (amistre64):
partial fractions is a technique used to rewrite an argument
OpenStudy (amistre64):
its easier to follow if you have a specific example to work thru tho
OpenStudy (unklerhaukus):
\[\frac 1 {x(x-1)}=\frac{A}{x} +\frac B {x-1}\]
OpenStudy (unklerhaukus):
if you were asked to integrate the first expression, it would be easiest to convert to the second expression before integration
OpenStudy (unklerhaukus):
then to solve for A and B
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OpenStudy (unklerhaukus):
then to integrate
OpenStudy (lgbasallote):
hmm well how about problems with trig sub AND partial fractions?
OpenStudy (unklerhaukus):
yuk
OpenStudy (lgbasallote):
yuk?
OpenStudy (unklerhaukus):
sorry that sort of problem seams like a nightmare
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OpenStudy (lgbasallote):
i know :/
OpenStudy (unklerhaukus):
im sure there are some people who would like that sort of problem but i am not one of them
OpenStudy (lgbasallote):
those guys who gave me brutal problems on the last question might...people like @lalaly @amistre64 and @FoolForMath ? :P
OpenStudy (lalaly):
hi:D
OpenStudy (lgbasallote):
hello :) i'm lgbasallote. nice to meet you lalaly
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OpenStudy (lalaly):
lol nice to meet you tooo
OpenStudy (lgbasallote):
enough of the getting-to-know...can you teach me how to solve trig sub + partial fractions combined? you're pretty good in brutal calculus so i thought ill ask you
OpenStudy (anonymous):
lalaly where are you from?
OpenStudy (anonymous):
and how did get the "99"? :p
OpenStudy (lalaly):
lol tai ive been on os for more than a year ... and i solved so many questions :D ... lg id be happy to ...
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OpenStudy (anonymous):
partial fractions in integration, is it definite or indefinite?
OpenStudy (anonymous):
remember to + C for the unknown
OpenStudy (anonymous):
and plug in co-ords to find C
OpenStudy (lgbasallote):
yay for lana \m/ indefinite would be nice Tai since definite just comes from indef
OpenStudy (anonymous):
well...just use the power and divide by it?
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OpenStudy (anonymous):
let's say x^1/4 becomes (x^5/4)/(5/4) which is 4/5(x^5/4)
OpenStudy (anonymous):
+ C
OpenStudy (lgbasallote):
but that's the power formula..not the partial fractions
OpenStudy (anonymous):
what do you mean by "partial fractions"?
OpenStudy (lgbasallote):
partial fractions,...uhh how are they explained....i dunno lol...
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OpenStudy (anonymous):
lol >_>
OpenStudy (anonymous):
the denominator is not factorisable, give me an example to work with plox
OpenStudy (lgbasallote):
that totally depicts my lack of mastery :P anyway...maybe a sample from the legendary @lalaly can hellp us both...
\(\Large \int \frac{e^x}{(e^x - 1)(e^x + 3)} dx\)
OpenStudy (anonymous):
lga 1st u have to put e^x=t
OpenStudy (lgbasallote):
uh-huh...
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OpenStudy (lgbasallote):
\(\large \int \frac{dt}{(t-1)(t+3)}\)
OpenStudy (anonymous):
eww
OpenStudy (anonymous):
ya gud lga
OpenStudy (lgbasallote):
so it's \(\large \frac{A}{t-1} + \frac{B}{t+3}\)
OpenStudy (lgbasallote):
i dont think this is gonna have trig subs though...
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OpenStudy (anonymous):
i never use partail formula ..i use always my trick to solve dis types of question
OpenStudy (lgbasallote):
mind sharing?
OpenStudy (anonymous):
yeah lol
OpenStudy (anonymous):
i'm kinda stuck
OpenStudy (anonymous):
pro people ^_^
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OpenStudy (anonymous):
you guys all @ uni?
OpenStudy (lgbasallote):
i think me and lalaly are...gurvinder though i think isnt are you?
OpenStudy (anonymous):
no, i'm lazy
OpenStudy (anonymous):
i'm 17, wbu guys?
OpenStudy (lgbasallote):
hmmm lana's taking a long time..must be some heck of a latex lol
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OpenStudy (lgbasallote):
and she's suddenly gone
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
committed suicide
OpenStudy (anonymous):
just kidding
OpenStudy (anonymous):
A/(t−1)+B/(t+3)
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OpenStudy (anonymous):
is that the f'(x)?
OpenStudy (anonymous):
or f(x)?
OpenStudy (anonymous):
A(t-1)^-1 + B(t+3)^-1 --> -A(t-1)^-2 -B(t+3)^-2
OpenStudy (unklerhaukus):
@gurvinder what is your trick?
OpenStudy (unklerhaukus):
can you apply to :
\[\frac1{x(x−1)}\]
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OpenStudy (anonymous):
he's joking, there's no trick
OpenStudy (unklerhaukus):
oh, lame
OpenStudy (anonymous):
yeah...:(
OpenStudy (lgbasallote):
i think it is the cover up method thing
OpenStudy (anonymous):
i wish there were shortcuts to mathematics...
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OpenStudy (anonymous):
-drinks coffee-
OpenStudy (lgbasallote):
choose C alway
OpenStudy (turingtest):
@lgbasallote I'd be happy to help you with such an integration problem if you still need the help
OpenStudy (lgbasallote):
well i'll be happy to be helped too @TuringTest after all i still do not know how to it haha lol =))
OpenStudy (anonymous):
ya tia have a trick ok..........i going to tell u all