Question

Factor completely 16y^2+25

Answer 1

@CAT2142276 have you studied complex numbers?
or
Is this your question?
\[16y^2-25\]

Answer 2

yes that is my question , i dont know how to write the little 2 with out the carrot button..

Answer 3

To write like that use equation:)

Answer 4

Ok let's factor
\[16y^2-25\]
We know
\[16=4^2\]
and \(25=5^2\)
so
\[4^2y^2-5^2\]
This can be written as
\[(4y)^2-5^2\]
Now we know
\[(a^2-b^2)=(a-b)(a+b)\]
Using this here we get
\[\huge (4y)^2-(5)^2=(4y+5)(4y-5)\]

Answer 5

oh okay thank you ;-)

Answer 6

@CAT2142276 Welcome to Open Study:D

Answer 7

how about this
\[4a^{2}-16a+16\]

Answer 8

@CAT2142276 I can help you here but if you close this question and post this one as new question. You'd get more users to help. Willy you do this?

Answer 9

okay