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Mathematics 15 Online
OpenStudy (coconut):

What are the possible number of positive, negative, and complex zeros of f(x) = –2x3 – 5x2 + 6x + 4?

OpenStudy (anonymous):

That has 2 negative roots and 1 positive and no complex roots. Plug in zero for y and factor a (2x +1), you are left with:\[-(2x + 1)(x^2 + 2x - 4) = 0\]That should be easier to solve.

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