Question

sove by x^2-6x+3=0 by completing the square?

Answer 1

Yes.

Answer 2

can you help me?

Answer 3

I think you mean "Solve for x^2-6x+3=0 by completing the square."

So what you want to do is, you have that -6, and half of that is -3, so you write


(x-3)*(x-3)

(your job is to expand this now and see what you get)

Answer 4

x=9 and x=3

Answer 5

No I want you to expand (x-3)*(x-3). It should start with x^2...

Answer 6

x^2-6x-9=-3-9

Answer 7

close, I think you are trying to do too many steps at once but you have the right Idea.

We know that
(x-3)*(x-3) = x^2 - 6x + 9.

We want to solve for
x^2 - 6x + 3 = 0 so now we do the old plus and minus trick...
= x^2 - 6x + 3 = 0
= x^2 - 6x + 9 - 9 + 3 = 0 and now we can substitute in the equation on top...
= (x-3)*(x-3) - 9 + 3 = 0
= (x-3)*(x-3) - 6 = 0
(x-3)*(x-3) = 6
= (x-3)^2 = 6
(x-3) = +-sqrt(6)
x = 3 +- sqrt(6) where "+-" means "plus or minus"

Answer 8

so is x=9 and x=3 right or no i didnt quite understand what u meant