Question

Find the coordinates of the points where C crosses the y-axis, giving your answers as simplified surds if C = (x+2)^2+(y-1)^2=4

Answer 1

since the yaxis is also the x=0 axis; just make x=0 and solve for y

Answer 2

do it

Answer 3

that's the part i got stuck @

Answer 4

what is 0+2?

Answer 5

2

Answer 6

what's 2^2?

Answer 7

and you tell me what's wrong here

Answer 8

either the equation is wrong or the exam paper has a mistake in it

Answer 9

or i'm just stupid

Answer 10

if the openstudy doesnt boot me out, sure :)

Answer 11

2^2 is ....

Answer 12

i just need an answer

Answer 13

(x+2)^2+(y-1)^2=4

(0+2)^2+(y-1)^2=4

2^2+(y-1)^2=4

im sure you do, but thats not how we play in here

Answer 14

i can do integration by parts

Answer 15

the 4s cancel out

Answer 16

you dont need to integrate by parts for this tho :)

Answer 17

good, the 4s cancel

(y-1)^2 = 0

Answer 18

so y=1

Answer 19

but it says answer in surd form?

Answer 20

y = 1 is what i would get too

Answer 21

sqrt(1) then

Answer 22

that would be SR(-1)

Answer 23

which is i lol

Answer 24

a surd is just the radical; and i think it means to keep exact answers

Answer 25

oh wait it's SR1...lmao

Answer 26

lmaoooo i can't believe i missed that out

Answer 27

:)

Answer 28

that's why i hate exams, esp british ones

Answer 29

the simplified surd would be 1 in my opinion

Answer 30

why?

Answer 31

tbh there must be something fishy...how is 1 a surd? >_>

Answer 32

because a simplified surd can be a rational or integer value

sqrt(4) simplifes to 2

sqrt(8) simplifies to 2 sqrt(2)

Answer 33

its not asking for a surd; its asking for the simplified form of it

Answer 34

so they're just putting that in to mess with your brains?

Answer 35

pretty much

Answer 36

can't you also do y^2+1=0?

Answer 37

hence y=SR-1

Answer 38

no

(y-1)^2 = 0

y-1 = sqrt(0) = 0

y = 1

Answer 39

yeah i was stupid for one whole hour...

Answer 40

btw i got to level57 in one day - yesterday

Answer 41

is that good?

Answer 42

dunno, ive never been less than a 99

Answer 43

so you're a moderator?

Answer 44

how would one apply for such a title?

Answer 45

its not an applied for job, its an invitation by the administrators

Answer 46

is the title bribe-able?

Answer 47

only kidding - wink wink

Answer 48

lol, you have to sacrifice chickens; or so ive been led to believe

Answer 49

:O

Answer 50

do eggs count?

Answer 51

chickens are too expensive

Answer 52

not according to the axiom; never count your chickens b4 they hatch

Answer 53

haha

Answer 54

so which really came first? the chicken or the egg?

Answer 55

that would make a good question on OS biology, if there's such a thing?

Answer 56

the chicken is the egg, so they have always coexisted; only thing is eggs are uncountable ... imo

Answer 57

so are you currently studying mathematics @ university?

Answer 58

are you some kind of wiz professor? :p

Answer 59

im getting a math degree yes

Answer 60

can you help me with this?

Answer 61

∫(x+1)(x+2)(x+3)(x−5)(2+2x3x)(e2x+2x)d

Answer 62

x

Answer 63

e^2x btw

Answer 64

prolly ... but last time there was a division inthere right?

Answer 65

yesss

Answer 66

what is the integral of (x+1)(x+2)(x+3)/(x-5)(2+2x^3x)(e^2x+2x) dX from 0 to 1?

Answer 67

i think your missing some exponential notations ^(..)

Answer 68

thats better

Answer 69

..... i come up with -.27691

Answer 70

how?

Answer 71

divination of course :)

Answer 72

lol

Answer 73

http://www.wolframalpha.com/input/?i=integrate+%28x%2B1%29%28x%2B2%29%28x%2B3%29%2F%28%28x%E2%88%925%29%282%2B2x%5E%283x%29%29%28e%5E%282x%29%2B2x%29%29+from+0+to+1

Answer 74

hahahaha^