Use differentials (or equivalently, a linear approximation) to approximate ln(0.91) as follows: Let ƒ(x)=ln(x) and find the equation of the tangent line to ƒ(x) at a "nice" point near 0.91. Then use this to approximate ln(0.91).

Approximation= ?

Question

Use differentials (or equivalently, a linear approximation) to approximate ln(0.91) as follows: Let ƒ(x)=ln(x) and find the equation of the tangent line to ƒ(x) at a "nice" point near 0.91. Then use this to approximate ln(0.91). 

Approximation= ?

anonymous · Answer

i got the answer which is -0.09...anyway you can show how you got it? 

I did it, but i'm pretty sure there's different ways to do it...

anonymous · Answer

|dw:1335560411353:dw|