Question

What are the solutions of the system y=x^2 - 3x + 2 ,y=4x -4

Answer 1

y=x^2 - 3x + 2 -(1)
y=4x -4 -(2)
Sub (2) into (1)
4x -4 =x^2 - 3x + 2
x^2 - 7x +6 =0
(x-6)(x-1) =0
x =6 or x=1
Now, substitute x =6 and x=1 (2) respectively.
When x =6
y=4(6) -4 = 24-4 =20
When x =1
y=4(1) -4 = 4-4 =0

Therefore the solutions are (1,0) and (6, 20)
Hope it helps

Answer 2

Thanks Roly Poly

Answer 3

Do you understand how to do it?

Answer 4

a little advice, since you provided the solutions and didnt really engage the asker; we will never really know if they understood ....

Answer 5

Oh.. Thanks for the advice!