About 11% of the population is math phobic. If two people are randomly selected, what is the probability that both are math phobic? What is the probability that at least one is math phobic?

Question

anonymous · Answer

Two independent events. Probability of both = P(A)*P(B)

anonymous · Answer

P(both phobic) = .11 * .11 = 0.121 or 12.1 %

anonymous · Answer

P(at least one) = 1-P(neither)

amistre64 · Answer

$$\frac{\binom{11}{2}}{\binom{100}{2}}$$

maybe?

zarkon · Answer

amistre64...that would assume you are only looking at a population of 100 people.

amistre64 · Answer

right, i was wondering if i could generalize the 11% like that

amistre64 · Answer

whats the earths population?

anonymous · Answer

No, it's better to just think of them as independent events with a set likelihood each time.

anonymous · Answer

Ahahaha.

amistre64 · Answer

the bigger my numbers the more it stabalizes at .012 ...  ;)

anonymous · Answer

Makin' the problem so complicated lols. But it's more accurate too, I suppose.

zarkon · Answer

we assume an infinite population...using 1,000,000 or infinity will yield almost the same result

amistre64 · Answer

.11*.11 = .0121  rught?

zarkon · Answer

yes