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Solve for x -3 1/2 = 1/2x + 1/2x + x. -5 1/2 -1 3/4 -1 1/2
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\[\huge -3\frac12=\frac12\cdot x+\frac12 \cdot x+x\] is this the given?
-7/2 x = x/2 + x/2 + x -7=x+x+2x(multiplying 2 on both sides) 4x=-7 x=-7/4=-1 3/4 third one...
yes ,i think that is given...kreshnik
@Sarkar how do you know there's \[\LARGE \frac12\cdot x\] instead of \[\LARGE \frac12x\] that wouldn't be : \[\LARGE \frac x2\] but \[\LARGE \frac12 +x \]
@CoreyContini -please use the draw option to write the question properly....
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I guess @Sarkar 's solution is correct then... well done.
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