A quadratic function passes through the point (-11, -21) and has a vertex at (-8, -48). Write the function in the form y = a(x - p)2 + q. What are the values of a, p and q?

The value of 'a' is

Question

A quadratic function passes through the point (-11, -21) and has a vertex at (-8, -48). Write the function in the form y = a(x - p)2 + q.  What are the values of a, p and q?

The value of 'a' is

saifoo.khan · Answer

This is same as,

a(x-h)^2 + k

saifoo.khan · Answer

a(x+11)^2 - 21

anonymous · Answer

i know p and Q but i dont remeber what do u put if there is not number for a just 1?

anonymous · Answer

and also would p be -8 since it says the vertex is -8,-48 ?

saifoo.khan · Answer

i made a mistake! :(
kill me..

saifoo.khan · Answer

a(x+8)^2 - 48

It will be this!

anonymous · Answer

hahahah i wont just wondering , cuz im not so good at it as u seee lol , :) thank you soo much so A can be considered 1?

saifoo.khan · Answer

Lol, you are way better than others..

Now after you have 
a(x+8)^2 - 48
use it to find the values for a.

$$    y = a(x+8)^2 - 48$$$$-21 = a((-11)+8)^2 - 48$$

anonymous · Answer

you seem to be extremly good in math helped me alot , thank you : )

saifoo.khan · Answer

Thankyou.
Math is fairly easy. ;)

Dont forget to hit good answer.
Tx.
@irena95

anonymous · Answer

best  answer ;p

saifoo.khan · Answer

Haha. thanks.

saifoo.khan · Answer

I used to be "good answer" about 10 days ago..