Question

integration help please

Answer 1

\[\int\limits 2x((4x^2)-10)^2\] can you explain to me how this becomes
\[((4x^2-10)^3)/10\]

Answer 2

sorry that is divided by twelve not ten

Answer 3

suppose, \( 4x^2 - 10 = u\) , then you have, \( 8x dx= du \)

Then the integration becomes \( \large \int \frac{u^2du}{4}\)

Answer 4

I thought in substituting I would need to find du=f'(x) dx. I see that is 8xdx. since we start with 2x dx wouldn't it be then that 4*du =2xdx? not du/4?

Answer 5

8xdx = du
2xdx = du/4