Question

Graph the following equation (image attached)

Answer 1

Start by finding the x-intercept(s)/y-intercept if any. To find the x-intercept (when the graph crosses the x-axis) you need to set y=0 and solve for 0=x^2+x-9, and this will yield the point(s) (x(found),0) graph those points. Then solve for the y-intercept which happens when x=0 which yields y=-9 so you have the point (0,-9). You can now graph an approximation. If you want more accuracy make a table where you put different x's and find their corresponding y-values (plot those points).

Answer 2

I've attached a graph... you need the general quadratic formula for the roots

x=-b/2a or x = -1/2 is the line of symmetry.... vertex (-1/2, -9 1/4)

Answer 3

OK. So so the vertexes are basically (-1/2 and -9 1/4) right?