Question

identify the factors of x^2 + 16 y^2 ?
I found the answer to be (prime) because they dont have any factors in common. Is that right?

Answer 1

Yes.

Answer 2

Yes, this is a prime one. :) the reason is already given in the answer :D

Answer 3

thank you for confirming :)

Answer 4

to be fair, it is prime across the reals

Answer 5

or is that the definition of prime?

Answer 6

Yes \( a^n +b^n\) is prime across the real when \(n\) is even.

Answer 7

thanks!