ABCD-rhombus. Angle PAQ = 56 degrees. Find angle B.
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OpenStudy (anonymous):
a figure would help
OpenStudy (anonymous):
OpenStudy (anonymous):
It looks like triangle ABP has two right angles?
OpenStudy (anonymous):
No, I just painted angle B
OpenStudy (anonymous):
|dw:1335770595202:dw|
do its \[\angle B= 90\]
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OpenStudy (anonymous):
\[B \neq90\]
OpenStudy (campbell_st):
look at the quadrilateral APCQ
angle QAP = 56 angle AQC = CPA = 90
then by angle sum of a quadrilateral angle PCQ = 124
next look
then by the property of opposite angles in a rhombus are equal
angle BAD = 124
angles DAQ + BAP = 124 - 56
= 68
OpenStudy (anonymous):
Thank you campbell_st:)
OpenStudy (campbell_st):
using opposite angles of a rhombus are equal
and angle BAD = angle BCD = 124
then angles ABC + ADC = 360 - 248
= 112
2ABC = 112
ABC = 56