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Mathematics 20 Online
OpenStudy (anonymous):

3x^2+13x-10

OpenStudy (anonymous):

= 0? Use the quadratic formula: \[ x_{1/2} = \frac{-b \pm \sqrt{ b^2 - 4ac }} {2a} \]

OpenStudy (anonymous):

a = 3, b = 13 and c = -10.

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Then, what is it? Factor it out? :-)

OpenStudy (anonymous):

yes factoring

OpenStudy (radar):

try (x+5) (3x- ??)

OpenStudy (anonymous):

You can use the formula to find a root for the equation. Suppose the root is x = 5. Then, (x+5) will divide with no remainder the original polynomial. It can be rewritten as (x+5)(3x - 2) :-)

OpenStudy (anonymous):

well i thought it wouls be this 3(x^2- - )

OpenStudy (anonymous):

would

OpenStudy (anonymous):

Neither 10 nor 13 is divisible by 3. That's not a common factor to it.

OpenStudy (anonymous):

are* divisible

OpenStudy (anonymous):

i kno

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