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3x^2+13x-10
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= 0? Use the quadratic formula: \[ x_{1/2} = \frac{-b \pm \sqrt{ b^2 - 4ac }} {2a} \]
a = 3, b = 13 and c = -10.
no
Then, what is it? Factor it out? :-)
yes factoring
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try (x+5) (3x- ??)
You can use the formula to find a root for the equation. Suppose the root is x = 5. Then, (x+5) will divide with no remainder the original polynomial. It can be rewritten as (x+5)(3x - 2) :-)
well i thought it wouls be this 3(x^2- - )
would
Neither 10 nor 13 is divisible by 3. That's not a common factor to it.
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are* divisible
i kno
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