Question

Simply this radical equation: square root of 108 + 3 square root of 50 + 5 square root of 12 + 4 square root of 18

Answer 1

opps.....I made a mistake
\[\sqrt{108}=\sqrt{2 \times 2 \times 3 \times 3 \times3}=6 \sqrt{3}\]

Answer 2

no im still confused!

Answer 3

All I did was factor 108. \[\sqrt{108}=\sqrt{2\times2\times3\times3\times3}\]
\[=\sqrt{2^{2}\times3^{2}\times 3} =\sqrt{2^{2}}\times \sqrt{3^{2}}\times \sqrt{3}\]
\[=(2 \times 3)\sqrt{3}=6\sqrt{3}\]

Do you see how I got this first term from \[\sqrt{108}\]?

Answer 4

You can factor each term of the expression this way.

Answer 5

You can factor each term of the expression this way.\[3\sqrt{50}=3\sqrt{2 \times 5 \times 5}=3\sqrt{2}\sqrt{5^{2}}=15\sqrt{2}\]