what is the solution set of the quadratic equation 8x^2+2x+1=0
a) {-1/2,1/4}
b) -1+√2, -1-√2}
c) {-1+√7/8, -1-√7/8}
d) no real solution

Question

what is the solution set of the quadratic equation 8x^2+2x+1=0
a) {-1/2,1/4}
b) -1+√2, -1-√2}
c) {-1+√7/8, -1-√7/8}
d) no real solution

anonymous · Answer

d

anonymous · Answer

Easiest method to solve is use the quadratic formula, $\large\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

anonymous · Answer

If you look at the term under the square root, $\large b^2-4ac$, if it's negative you know that there is no real solution.

anonymous · Answer

how do i know what a, b, and c are? to plug it in

anonymous · Answer

$a$ is the coefficient of the $x^2$ term, $b$ is the coefficient of the $x$ term, and $c$ is the constant. So in this example, $a=8$, $b=2$, and $c=1$.

anonymous · Answer

ax^2+bx+c? is that the quadratic eqaution

anonymous · Answer

Right, $ax^2+bx+c$, and you plug $a$, $b$, and $c$ into the formula.

anonymous · Answer

great! thanks!

anonymous · Answer

Sure thing.