Question

On a day when the air temperature is 34 degrees Celsius, a can of soft drink is taken from the fridge at a temperature of 4 degrees Celsius at 2pm. Thereafter the temperature of the can satisfies the differential equation dT/dt=0.1(34-T), where t is the number of minutes after 2pm. What is the temperature of the can at 2:15pm? At what time does the temperature reach 30 degrees Celsius?

Answer 1

so far I have... \[\ln (34-T)=0.1t+C\] but not sure how to proceed from here...