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How to apply the second part from the question in part (a)
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\[\frac{-\frac{x^4}{2!} + \frac{x^8}{4!}-\ldots}{x^2} = -\frac{x^2}{2!} +\frac{x^6}{4!}- \ldots \] \[\left[ -\frac{x^3}{3\cdot2!} + \frac{x^7}{7\cdot 6!}+\ldots \right]_0^1\]Something like this maybe?
@Ishaan94 are we apply -1 ??
take the maclaurin of cos(x^2) for a couple of terms and compare it to the expansion from the first see if T(x^2), where T(x) is the expansion from the top, matches the cos(x^2) expansion
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