Question

2x+square root of x -6=0?

Answer 1

let us assume sqrtx = y
therefore x = y^2
now plug in these values in above equation and solve for y

Answer 2

alright.
could you finish just i understand exactly?

Answer 3

\[2y^2 +y -6 =0\]
now solve for y

Answer 4

-6

Answer 5

2y^2+y=-6

Answer 6

then...?

Answer 7

got lost :/

Answer 8

\[2y^2 + y - 6=0\]
\[2y^2 + 4y -3y - 6=0\]
\[2y(y + 2) -3(y + 2)=0\]
\[(y + 2)(2y -3)=0\]
therefore
either y + 2 = 0 or, 2y-3 = 0
therefore y = -2 or, y = 3/2
now plug in these value in y = sqrtx

Answer 9

ty ty ty