Question

\[\LARGE \int {9x^2-3\over x\sqrt 3+1}dx\]

Answer 1

can you divide numerator with denominator ??/ and express it in terms of remainder???

Answer 2

dIpanic did somthing similar in my previous integral question, but honestly I didn't get a thing!.. I can just rewrite it like:
\[\LARGE \int \frac{9x^2}{3\sqrt3+1}-\frac{3}{x\sqrt3+1}dx\]
and that's all !

Answer 3

\[\LARGE \int \frac{9x^2}{x\sqrt3+1}-\frac{3}{x\sqrt3+1}dx\]

Answer 4

How about a polynomial long division first?

Answer 5

I'll be back in 10 mins

Answer 6

no ... divide it,

this is gong to be boring!!!