2. Choose the equation below whose axis of symmetry is x = 0. (1 point)
y = x2 + 2x
y = x2 − 16x + 58
y = x2 + 2
y = x2 − 4x + 2

Question

2.   Choose the equation below whose axis of symmetry is x = 0.  (1 point)
y = x2 + 2x
y = x2 − 16x + 58
y = x2 + 2
y = x2 − 4x + 2

anonymous · Answer

x=0 is the vertical line through 0 (the y-axis)

So which has a vertex on the y-axis?

anonymous · Answer

I dont know

anonymous · Answer

There are a few ways of knowing... one way is to know the basic graph of y = x^2 and see that y = x^2 + 2 is a vertical shift up 2 units.  

Or you can use the handy formula for the x-value of the vertex:    x = -b/(2a)  to see that y=x^2 + 2 is the only one that gives zero for this.