Question

Divide. (18x^3 + 12x – 3x) ÷ 6x^2

Really confused on how to do this, If you could go step by step it would really help .

Answer 1

are u still there?

Answer 2

yes

Answer 3

r u sure that you have written the question correctly?

Answer 4

yes.

Answer 5

ok. so within the parens, you can combine 12x-3x to get 9x.

so now it looks like \[(18x^{3} + 9x)\div6x ^{2}\]

Answer 6

ok?

Answer 7

okay.

Answer 8

so now, for the binomial in parens do you think that there are any common factors?

Answer 9

\[9x(2x ^{2} +1)\div6x ^{2}\]

Answer 10

sorry i wasnt at my computer

Answer 11

9x and 2x^2

Answer 12

well you have 9x in the numerator and 6x^2 in the denom.

this will cancel out to 3/2x

so final answer is \[(6x^{2}+3)/3x\]

Answer 13

thanks !!