Question

Derivitive for e^(-2t)?

Answer 1

do you know chain rule?

Answer 2

\[-2e ^{-2t}\]

Answer 3

yeah i do. i think the answer is -2e^(-2t)

Answer 4

but its not working in the problem i have so think i'm doing something wrong here.

Answer 5

\[\LARGE (e^u)'=e^u\cdot u'\]

leads you in the answer you got.
or..
\[\LARGE -\frac{2}{e^{2t}}\]

Answer 6

(fog)' = (f'og) x g'

Answer 7

ok thank you very much :)

Answer 8

you're welcome...