Question

What is the equation of the line that passes through the point (2, 3) and is perpendicular to the line y = –x – 3?

Answer 1

for the line y = -x -3 the slope(gradient) is \[m _{l} = -1\]

a perpendular line has a gradient od \[m _{p} = \frac{-1}{m _{l}}\]

\[m _{p} = \frac{-1}{-1} \]

gradient of the perpendicular is m = 1

use the point gradient formula

m = 1, y1 = 3 and x1 = 2

\[y - y _{1} = m(x -x _{1})\]

to find the equation of the line

Answer 2

these are the choices i have:
y = x + 5

y = x + 1

y = –x – 1

y = –x + 5

Answer 3

y - 3 = 1(x - 2)
y - 3 = x - 2

just simplify add 3 to both sides

Answer 4

so.. y = x+1 ?