Question

What is the third-degree polynomial function such that f(0) = -12 and whose zeros are 1, 2, and 3?

A) f(x) = 4x3 - 24x2 + 22x - 24
B) f(x) = 2x3 - 12x2 + 22x - 12
C) f(x) = 4x3 + 24x2 - 44x - 24
D) f(x) = 2x3 + 12x2 - 22x - 12

Answer 1

Start with the fact that you have these zeros:
1,2, and 3
That gives me three linear factors:
(x-1)(x-2) and (x-3)

Multiplying those out will almost get you there, but then you need f(0) = -12, so you'll have to multiply the whole equation by some number to make that true. Give that a try and ask me any question that come up.