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OpenStudy (anonymous):

If S'(t) = 30t^1/2, S(0) = 22000 and S(t) = 41000, find t. my answer choices are 107, 161, 97, 102

OpenStudy (anonymous):

hmmmm shld i give the answer away again?

OpenStudy (anonymous):

hahahahah

OpenStudy (anonymous):

yes yes yes you should!

OpenStudy (anonymous):

you are so smart

OpenStudy (anonymous):

hahaha

OpenStudy (anonymous):

Make an educational guess first.

OpenStudy (anonymous):

I found 161 but I do not think it is right

OpenStudy (anonymous):

haha my equation was wrong give me one more sec

OpenStudy (anonymous):

Can you write the original function s(t)

OpenStudy (anonymous):

I think my original function is off..

OpenStudy (anonymous):

Can you write it. I can tell you if it's off or not.

OpenStudy (anonymous):

wait sorry bat that i am back

OpenStudy (anonymous):

S(t)= 30x^2

OpenStudy (anonymous):

its all good! Im just re working it on paper trying to see where i went wrong

OpenStudy (anonymous):

You are suppose to integrate s'(t)

OpenStudy (anonymous):

no S(t)=20x^(3/2)+22000

OpenStudy (anonymous):

S(t)=30x^3/2 like that?

OpenStudy (anonymous):

@samjordon The problem is that he doesn't know how to integrate. Don't just show him the function explain the steps.

OpenStudy (anonymous):

oh okay I see what I did wrong, so my equation is 20x^(3/2) +22000

OpenStudy (anonymous):

@taffytwink Do you know how we get that from S'(t) = 30t^1/2?

OpenStudy (anonymous):

yea cause 30/(3/2) = 20 and that leaves me with the integral of 30t^1/2

OpenStudy (anonymous):

I get how to come up with the equation but what do I do with the 41000

OpenStudy (anonymous):

The ingetral will give you 20t^3/2 + B where B is just a constant. You solve for B by using the function s(0)=22000. This gives you B=22000 After that you have S(t)=20t^(3/2)+22000 we are now trying to find what t is when s(t)=41000 just replace it 41000=20t^(3/2)+22000 Now you have an equation with one unknown t solve for t

OpenStudy (anonymous):

yes sorry guys my mom was driving me crazy but i am back

OpenStudy (anonymous):

OHHHH okay

OpenStudy (anonymous):

lemme work it out

OpenStudy (anonymous):

nah he is in business calc he isnt in hswe can give away the answer

OpenStudy (anonymous):

haha i agree with @samjordon

OpenStudy (anonymous):

im calculating it right now

OpenStudy (anonymous):

What? Anyways you need to practice integrations. You mest up the integration. You didn't know how to solve for t after finding s(t). Just practice on easier problems and you will get the hang of it.

OpenStudy (anonymous):

yea thank you so much for breaking it down for me, medal worthy acquaintance

OpenStudy (anonymous):

I got 97 but it wasnt exact, did I do it wrong?

OpenStudy (anonymous):

the answer is 97

OpenStudy (anonymous):

i gota that tooo

OpenStudy (anonymous):

YES sweet thank you so much

OpenStudy (anonymous):

not a problem

OpenStudy (anonymous):

im about to post another

OpenStudy (anonymous):

hmmm someone is posting the similar questions as uand is on ur post hmmmm interesting

OpenStudy (anonymous):

hahaa me and my buddy are trying to do this together

OpenStudy (anonymous):

we go to school together

OpenStudy (anonymous):

hahaha my assumption is correct

OpenStudy (anonymous):

Haha we're doing our homework together and our teacher is a joke. Would you mind taking a look at the question I posted? @samjordon

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