Question

4log[12](2)+log[12](x)=log[12](96)

Answer 1

start with
\[\log_{12}(2^2)+\log_{12}(x)=\log_{12}(96)\]
then go to
\[\log_{12}(4x)=\log_{12}(96)\] and then it should be easy

Answer 2

i think there's an error... it should be 2^4?

Answer 3

\[\log_{12}(2^4)+\log_{12}(x)=\log_{12}(96)\]

Answer 4

yes i made a mistake

Answer 5

go with dpalnc answer

Answer 6

\[\log_{12}(16x)=\log_{12}(96)\]

Answer 7

from there can you solve for x?

Answer 8

x=6 is that correct?

Answer 9

yes

Answer 10

does 2log[2](2)+2log[2](6)-log[2](3x)=3 equal x=16???

thanks for the help