Question

You can verify the zeros of the function y=x^2+6x-7 by using a graph and finding where the graph

A. is at a minimum

B. is at a maximum

C. crosses the x-axis

D. crosses the y-axis

Answer 1

A plot is attached.

Answer 2

b

Answer 3

A. x = -3
C. { x = -7, x = 1}
D. y = -7

Answer 4

i dont get it

Answer 5

Had to switch web browsers. LaTex no rendering properly with Safari.
Set y to zero and solve for x \[x^2+6 x-7=0 \]\[(x-1) (x+7)=0 \]\[\{x=1,x=-7\} \]
Take the derivative of the equation\[6+2 x=0\]and solve for x to obtain the minimum y.\[x=-3 \]The plot allows one to visually verify the algebraic results.