Question

what is the equation of the line passing through the points (-2,2) and (3,-1)

a. y=-5/3x+4/3
b. y=x-4
c. y=-3/5x+4/5
d. y=-3x+8

Answer 1

do you know the formula

Answer 2

The general form of a line is y = mx + b. Using this, you can find your answer. It really helps to plot the points on a plane.

Answer 3

\[\LARGE y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\]
\[\LARGE y-2=\frac{-1-2}{3-(-2)}(x-(-2))\]
\[\LARGE y-2=\frac{-3}{5}(x+2)\]
\[\LARGE y-2=\frac{-3}{5}x-\frac{6}{5}\]
\[\LARGE y=-\frac{3}{5}x-\frac{6}{5}+2\]
\[\LARGE y=-\frac{3}{5}x-\frac{6}{5}+\frac{10}{5}\]
\[\LARGE y=-\frac{3}{5}x-\frac{4}{5}\]

Answer 4

do you know the answer?

Answer 5

you're kidding right?? :)

Answer 6

sorry my bad, it's not - it should be +
this is final row
\[\LARGE y=-\frac35x+\frac45\]

Answer 7

okay got! :)