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Find the limit \[\lim_{y \rightarrow 2-} (y-1)(y-2)/y+1 \]
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do we use factorizing method here?
just plug the number in, and think about which terms will be positive and negative just to the left of 2
oh wait, what am I saying? just plug it in...
1/3 .. right?
but in the book the answer is 0 ?
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(2-1)(2-2)=0
\[\lim_{y\to2^-}{(y-1)(y-2)\over y+1}\]look at the numerator to see why it's zero
(1)(0)/(2+1) = 0/3 = 0
oh yea right .. I forgot multiplication of numerator .. Thanks
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