Question

Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).

Answer 1

so the equation of the line tells us that the slope of 2x-3y=3 is:

y= (-3+2x)/3
y= 2/3 x -1

Therefore slope is: 2/3

the slope of the perpendicular line is the Negative Inverse of the line slope, so that would be:

-3/2= m (slope of the perpendicular line)

Therefore the equation of the line that is perpendicular to y= 2/3 x -1, is therefore:


y= -3/2 x -1

Answer 2

That' s not in my answer choices.

Answer 3

what is in ur answer choices?

Answer 4

y=2/3x-10

y=2/3x+10

y=-3/2x-10

y=-3/2x+10

Answer 5

oh okey, so this is what you have to do; you have to figure out the value of b.

So we got the solve correct, which is m= -3/2

now we need to find b, y=mx+b ==> y=-3/2x+b, Plug in the point (-8,2) to find b.

2=-3/2 * -8 +b

-10=b

therefore the correct answer is the third choice y=-3/2x-10

Answer 6

Can you help me with some others please?