Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6) y=1/3x+7 y=-3x+3 y=1/3x+3 y=-3x+7
since we have a point on the line we want, we need the slope. in order to be parallel, we must have the same slope as the given line. what's the slope?
-1
nope.. y = -3x + 12 what's the slope of this line? remember y=mx+b, where m is the slope.
-3?
ok good.
so now you have slope, m=-3, and a point the line goes through, (-1, 6) we can put that in point-slope form: y - y1 = m(x - x1)
once you have that, do some algebra and solve for y so you can make the appropriate choice... :)
How do I put it in the Slope-point form?
sorry, (x1, y1) is the point (-1, 6), and m is our slope. copy my drawing and fill in those boxes. |dw:1335992091778:dw|
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