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What is y = x^2 -16x + 40 written in vertex form?
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help?
Do you know how to complete the square?
no :/
\[y=x ^{2}-16x+40\] Do you know how to do difference of squares?
no ma'am :/
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the equation is in standard form, therefore, it is y=x^2+bx+c divide your b value by two and square it
oh so that means y = (x - 8)^2 + 48
No, once you have your value, square it.
You should get 64
oh so ... y = (x - 16)^2 + 64 ?
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y= (x^2-16x+64)-64+40
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