(x - 6)(x + 6)
\[(a+b)(a-b)=a^2-b^2\]
Now, tell me what you think.
(x-6)(x+6) x times x = x^2 -6 times 6 = -36
Special form: (a+b)(a-b)=a^2-b^2
just multiply a by the x and 6 than mulitply the 6 by the x and 6
than all you have to do is simplify it
Obviously not typing fast enough to keep up here.....LOL
It can be demonstrated from the form\[(a+b)(a-b)=a^2+\underbrace{[ab-ab]}_0-b^2\]
so x^2+6x-6x-36 someone correct me if I am wrong
you also could just distribute so x(x+6)-6(x+6)
than just get rid of the 6x's and get x^2-36 or x^2+36
(x - 6)(x + 6) this is the difference of square \[(x-6)^2\] \[x^2-12x+36\] thats the answer
x^2 -36
yep my answer of x^2-36 was correct I checked
that would only be the answre if the question is the question was (x-6)^2 @GoldRush18
but thethe question is (x-6)(x+6)
oh ok guess i misinterpreted it
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