what is the square root of 81x to the 6th power, y to the 3rd power?
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OpenStudy (anonymous):
what is square root of 81??
OpenStudy (anonymous):
\[\sqrt{(81x)^6 \cdot y^3}\]??
OpenStudy (anonymous):
No its Square root of 81X to the 6th Power Y to the 3rd Power?
OpenStudy (anonymous):
\[\sqrt{81 \cdot x^6 \cdot y^3}\]
OpenStudy (anonymous):
Use the equation button below and write what is your question??
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OpenStudy (anonymous):
@ Cashmere, that is correct without the multiplication signs in between.
OpenStudy (anonymous):
LOLOL :D
OpenStudy (anonymous):
When you don't write anything between them it means multiplication by default
OpenStudy (anonymous):
xy = x.y
OpenStudy (anonymous):
The multiplication sign is inferred to be there.
Let's break it up, by the distributive property. \[\sqrt{81} \sqrt{x^6} \sqrt{y^3}\]
You know what the square root of 81 is.
Remember that\[\sqrt{x} = x^{1/2}\]Hence, we get\[x^{6/2}\] and \[y^{3/2}\]
Putting it all back together, we get\[9x^{6/2} y^{3/2}\]
What is 6/2?
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