what is the square root of 81x to the 6th power, y to the 3rd power?
what is square root of 81??
\[\sqrt{(81x)^6 \cdot y^3}\]??
No its Square root of 81X to the 6th Power Y to the 3rd Power?
\[\sqrt{81 \cdot x^6 \cdot y^3}\]
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@ Cashmere, that is correct without the multiplication signs in between.
LOLOL :D
When you don't write anything between them it means multiplication by default
xy = x.y
The multiplication sign is inferred to be there. Let's break it up, by the distributive property. \[\sqrt{81} \sqrt{x^6} \sqrt{y^3}\] You know what the square root of 81 is. Remember that\[\sqrt{x} = x^{1/2}\]Hence, we get\[x^{6/2}\] and \[y^{3/2}\] Putting it all back together, we get\[9x^{6/2} y^{3/2}\] What is 6/2?
3
Exactly. So when what is the exponent on x?
3
Exactly. So then our final expression would be?
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