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∫[-a,9] [x^2+x]
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First, find the indefinite integral of x^2+x
Remember, ∫ ax^n dx=(a/n+1)*x^(n+1)
how do i find the indefinite integral?
∫ ax^n dx=(a/n+1)*x^(n+1)
∫f(x)+g(x) dx=∫f(x) dx+∫ g(x) dx
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Then,\[\int\limits_{a}^{b}f(x)dx=F(b)-F(a)\]
so i do (9^2+9)-((-a)^2-a)??
No, you must first find the indefinite integral.
sorry i am so confused about how to find the indefinite integral
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