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which is the equation of the line that passes through (-2;-1) and (-4;-3)
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Find the slope, then use the point/slope form to get the equation of the line. If you need it in slope/intercept form or general form, you will have to do a little algebra to make it fit the desired specification.
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Find the slope:\[m=\frac{y_2-y_1}{x_2-x_1}=\frac{-3+1}{-4+2}=1\]
Point/slope form\[y-y_1=m(x-x_1) \implies y+3=1(x+4) \implies y=x+1 \implies x-y=-1\]
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The equations given there are the line in point/slope form, slope/intercept form, and general form.
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