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Mathematics 17 Online
OpenStudy (anonymous):

Erica was out of town for a month, so she had her friend Sara check her mailbox. Each day, Sara would count how many different types of mail Erica received and then place the mail in a box inside Erica's apartment. The table below shows how many pieces of each type of mail Erica received during the month. Erica's Mail Received in a Month Type of Mail Number of Pieces Bills20 Cards6 Junk Mail24 Magazines8 Advertisements38 Wrong Address 4 According to the table, if Erica drew two pieces of mail randomly from the box, without replacement, what is the probability she would draw out

OpenStudy (anonymous):

what is the probability she would draw out a wrong address

OpenStudy (anonymous):

1/25 is the chance she will draw a wrong address, if she draws 4 times, that would be 1/25 times 4, that would equal 4/100

OpenStudy (anonymous):

So if I am right, it would be 4/100 and that can be simplified to 1/25

OpenStudy (anonymous):

THats not one of the answers

OpenStudy (anonymous):

oh, sorry then, It has been a while since I have done probability

OpenStudy (anonymous):

let me go read up on it quick then get back here

OpenStudy (anonymous):

A 3/2475 B 3/2500 C 4/2475 D 1/625

OpenStudy (anonymous):

(4/total)*(3/total-1)

OpenStudy (anonymous):

1st time round prob= 4/total 2nd time, theres 1 less , so = 3/(total-1)

OpenStudy (anonymous):

I dont get it?

OpenStudy (anonymous):

but wouldn't that equal 1/825?

OpenStudy (anonymous):

but thats not one of the answers

OpenStudy (anonymous):

exactly

OpenStudy (anonymous):

let me see....

OpenStudy (anonymous):

let me try to get someone here that knows tis...

OpenStudy (anonymous):

its ok I have another question that i need help with too

OpenStudy (anonymous):

post the one here while i try to get someone here

OpenStudy (anonymous):

it was C

OpenStudy (anonymous):

working pls

OpenStudy (anonymous):

could you explain it @ZhangYan

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