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Mathematics 18 Online
OpenStudy (anonymous):

Can I get some help?

OpenStudy (noseboy908):

with what?

OpenStudy (anonymous):

Find the perimeter of triangle CDE. Round to the nearest tenth. 90.0 18.0 14.3 10.5

OpenStudy (noseboy908):

uhh, sorry but I cannot help with you with that, but best of luck finding someone who can

OpenStudy (anonymous):

can someone please help mee!!?

OpenStudy (anonymous):

Do you know the distance formula?

OpenStudy (anonymous):

No .

OpenStudy (anonymous):

The distance formula is the square root of (x2 - x1)^2 + (y2-y1)^2 You have to make this calculation for all three of these lines. I'll help you with the first one

OpenStudy (anonymous):

whats the answeeerrr ?

OpenStudy (anonymous):

Lets take the top left line on your graph, CD. The point at C is (-3,1) and D is (1,4) So plug these in for your formula above and you have (1 - -3)^2 + (4 - 1)^2 = 4^2 + 3^2 =16+9 =25 sqrt(25) = 5 So your line CD = 5

OpenStudy (anonymous):

now you have to do this for the other two lines, and to find the perimeter you just add your 3 answers together

OpenStudy (anonymous):

This link will teach more about the distance formula http://www.purplemath.com/modules/distform.htm

OpenStudy (anonymous):

is the answer 18.0?

OpenStudy (anonymous):

I dont know because it will take me a couple of minutes to do the other two just follow what I have done and if the other two lines add to 13, then add the line I did which is 5 and that means you would have 18

OpenStudy (anonymous):

But from the looks of the picture and the answer I got for the first line, 18 is the only answer that makes sense because the other two lines look slight bigger than the 5 that we found, 90 is way to big and 10 is way to small. And it doesn't look like its 14.5 either.

OpenStudy (anonymous):

still need help?

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