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A curve has the slope 2x+3 at each point (x,y) on the curve. What is an equation for this curve if it passes through the point (1,2)
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I keep getting 2x^2+x-1 as my asnwer but the answer is y=x^2+3x-2
i used y-y1 = m(x-x1) and subsitited m with 2x+3 and the x and y with (1,2).
im not sure what im doing wrong
write down differentiatial eq with initial condition y'=2x+3 y(1)=2 y=x^2+3x+C 2=1^2+3+C 2=4+C C=-2 y= x^2+3x-2
to go from y' to y , I integrated it
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oh ok. I see. I was doing something else completely different. This makes sense. Thanks. It was so easy and i cant belive i couldnt figure it out
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