Question

How would you solve 1/cot2x+1?

Answer 1

cot2x = cos2x/sin2x
Then cos2x = 2cosxsinx I think.....similarly sin2x......So, you can keep going at it until it is rather simplified nicely.

Answer 2

i don't understand how you got cos2x = 2cosxsinx... @GT

Answer 3

It was one of the theorem thingies....I don't remember....was just getting you started on the path. Need to look up on google to confirm.

Answer 4

don't see that theorem anywhere in our identites box in our textbook.

Answer 5

My mistake.

Here is the right one.

cos(2x)
= cos(x+x)
= cos(x)cos(x) - sin(x)sin(x)
= cos²(x) - sin²(x)

Answer 6

the property is cos2x + sin2x = 1 though....?

Answer 7

@saifoo.khan can you please help with this one? I am wandering off into some weeds that don't get to the answer.

Answer 8

cos^2x + sin^2x = 1. Correct. That is "squared".

Answer 9

beyond confused, thanks for baring with me through all the confusion..

Answer 10

Is that what you meant by cot2x?

Answer 11

i meant it cot^2x, forgot that sign!

Answer 12

cot^2x is not same as cot2x. When I saw cot2x, I thought it was cot(2x).

Answer 13

so sorry! typo!