The probability that a young Canadian plays soccer in the summer is 0.57. The probability that a young Canadian plays hockey in the winter is 0.83. Assuming that these are independent events, If a young Canadian is chosen at random, what is the probability that they play hockey or soccer?

Question

daenio · Answer

@Directrix

anonymous · Answer

sorry it says "or" i should learn to read

anonymous · Answer

assuming "or" means one or the other or both, add them up and then subtract the product

daenio · Answer

But what am I substracting from? 0.57+ 0.83- 1.4
What do I do from there?

anonymous · Answer

$$.57+.83-.57\times .83$$

daenio · Answer

Alright thanks man.