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You have a matrix A for Ax=0 Linear independence states that in order the columns for matrix A to be linear independent that Ax=0 must only have the trivial solution. Is this true?
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We can row reduce the augment matrix to see if there is a zero row or in other words a free variable. But what's confusing me is that if there is if x was a zero vector right?
Another thing is that my book showed that the augmented form proved that the columsn were lin independent BUT the last row was 0 0 19 0 How can 19=0??? there is no solution!!!
your first statement is true
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