Question

Attachment.

Answer 1

I'll brb, need to do something.

Answer 2

no

Answer 3

um can i assume that it is a 45-45-90 degree triangle?

Answer 4

because i don't think you can solve it with only one given length o.0

Answer 5

This is the correct one, I put the wrong file

Answer 6

3/2 is the answer.
Cross Street is the hypotenuse of the right triangle. The midpoint of the hypotenuese of a right triangle is equidistant from the vertices of the triangle.

Answer 7

Oh, that's the wrong file. I attached the correct one right above your answer

Answer 8

x = 3 --> Check it.
AP * PB = CP * PD --> If two chords intersect inside a circle, the product of the lengths of one chord is equal to the product of the segments of the other.

To get y, I'm doing EQ*QD = AQ*QB --> same theorem

Answer 9

If two chords intersect inside a circle, then the product of the segments of one chord equals the product of the segments of the other chord.
http://www.cliffsnotes.com/study_guide/Segments-of-Chords-Secants-Tangents.topicArticleId-18851,articleId-18828.html

Answer 10

EQ*QD = AQ*QB
14*y = 8*7
y = (8*7)/14 = 4

Answer 11

AP = 3
PQ = 4
QB = 7
EQ = 4
PD = 12

Answer 12

Wait, how did you get PD??

Answer 13

I did all that while you were over at FB :)

Answer 14

PD = 6*3 = 18. Better check my arithmetic. I just messed up somebobody's answer on another problem. She should have checked. o.0

Answer 15

Did you follow how I solved for x and y -- the theorem and the algebra?

Answer 16

Oh, I wasn't on FB :P I was doing a project that's due tomorrow haha. But okay, I see.

Answer 17

8x^2+10x+1/2x+1 This a long division problem, did I type it correctly?

Answer 18

@kjohns0115 Are you on the right question..?

Answer 19

yes

Answer 20

The answer is 4x+3-2 over 2x+1, I need a clear understanding of the anwer.

Answer 21

It's already solved by Directrix