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Here's the theorem we will need. If two secant segments are drawn from a point outisde a circle, the product of the lengths(C+D) of one secant segment and its exteranal segment(D) equals the product of the lengths (A+B) of the other secant segment and its external segment(B). http://www.mathwarehouse.com/geometry/circle/tangent-secant-side-length.php
Pass is 8.2 + 6 = 14.2 feet to the nearest tenth. I got x = 8.2 to the nearest tenth. Check my arithmetic.
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That's it, I suppose. I'm about to close shop.
Aw, okay /: good night then
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