Question

Tina has 11 balls. Every ball is a different color. She randomly lines the balls up next to each other. How many different ways can the 11 balls be lined up?


A. 11!

B. 10!

C. 12!

D. 9!

Answer 1

Ways of placing first Ball = 11
Ways of placing second after first is already placed = 10
Ways of placing third after second is already placed = 9
Ways of placing fourth after third is already placed = 8
Ways of placing fifth after fourth is already placed = 7
Ways of placing sixth after fifth is already placed = 6
Ways of placing seventh after sixth is already placed = 5
Ways of placing eighth after seventh is already placed = 4
Ways of placing ninth after eighth is already placed = 3
Ways of placing tenth after ninth is already placed = 2
Ways of placing eleventh after tenth is already placed = 1
So total Ways 11*10*9*8*7*6*5*4*3*2*1 = 11!