Solve x+12/x+4=x/x+8
\(\LARGE \frac{x+12}{x+4} = \frac{x}{x+8}\) that's the question right?
yes
why don't you try cross multiplying..you know how right?
Yeah i did that but I keep getting stuck. i got down to x^2+20x+20=x^2+4x and then just got stuck
good one! now put x^2 + 4x on to the left side....subtract x^2 from both sides first what do you have?
oh okay i tried that. so20x+20=4x oh wait then you have to subtract 20x from both sides rights?
no no..you always subtract the SMALLER one...so subtract 4x from both sides
yeah but if you do that then there is nothing left on the left side.. how does that work?
btw..there was a problem with your (x+12)(x+8) that should be equal to x^2 + 20x + 96 because 12 x 8 is 96 NOT 20..got it? :)
ohh i added it oops :P okay lemme start over
no no..it's okay..let's carry on from 20x + 96 = 4x
there wasnt any big changes on the 96 anyway..so it wont influence our solution so far
so...you subtract both sides by 4x what do you have?
16x+96 but i didnt think you could leave one side with nothing
where'd that equal sign go? what's 4x - 4x?
... 0 ha okay i feel kinda dumb so 16x+96=0 then you subtract 96?
RIGHT!!! \(\checkmark\) :DDD
and then 16/-96=-6?
you got it! :DDD
but that's -96/16 but i think you got the idea haha
Thanks :) oh ha yeah
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